**How to factor any trinomial as a trinomial with a leading coefficient of 1.**

1) Multiply

**a * c**to get the new "

**c"**value and give "

**a"**, a value of 1. i.e. 2x^2 + 7x + 6 = 0. Multiply 2 * 6 = 12. Put in 12 for "c" and 1 for "a".

Your new trinomial is;

**x^2 + 7x + 12 = 0**

2) Factor with leading coefficient having a value of 1 and solve for x. (factors for c that add up to equal b)

i.e. (x + 3) (x + 4) = 0,

**x = { -3, -4}**

3) Divide solutions by the

**original**leading coefficient ( In this example the original value for "a" was 2). You’re done!

i.e.

**x = {-3/2, -2} (2x +3) (x + 2)**

My math teacher in high school taught me this trick. I found it very useful until I forgot it. I am now in Calculus in college, and I really wanted to remember this trick! Thanks for posting this on your blog; I am now able to factor problems much faster on my calc exam!

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